Answer:
pls sorry i dont know the answer can you say the answer of it any one can to me
i also needed the answer toooooooooo..............................................................
Step-by-step explanation:
Replace x with -4 so it would be:
f(-4)= 2(-4)=-8
-8 is your answer
It is a geometric sequence
an=a1(r)^(n-1)
a1=first term
r=common ratio
n=which term
first term is 1
common ratio is 5
an=1(5)^(n-1)
that is the equatin/formulf for the nth term
if you want a summation formula of the sequence to the nth term
Sn=
![\frac{a1(1-r^{n})}{1-r}](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba1%281-r%5E%7Bn%7D%29%7D%7B1-r%7D%20)
in this case
Sn=
![\frac{1(1-5^{n})}{1-5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%281-5%5E%7Bn%7D%29%7D%7B1-5%7D%20)
or
Sn=
![\frac{1-5^{n}}{-4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1-5%5E%7Bn%7D%7D%7B-4%7D%20)
so in this case
up to 5th term
S5=
![\frac{1-5^{5}}{-4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1-5%5E%7B5%7D%7D%7B-4%7D%20)
S5=
![\frac{1-3125}{-4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1-3125%7D%7B-4%7D%20)
S5=
![\frac{-3124}{-4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-3124%7D%7B-4%7D%20)
S5=781
anyway
![a_{n}=(5)^{n-1}](https://tex.z-dn.net/?f=%20a_%7Bn%7D%3D%285%29%5E%7Bn-1%7D%20)
is the nth term
and
Sn=
![\frac{1-5^{n}}{-4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1-5%5E%7Bn%7D%7D%7B-4%7D%20)
is the summation up to the nth term
Answer:
7
Step-by-step explanation:
So, substitute in your 4 for r, 2(3) + 1. Multiply 2 and 3 to get 6 and then add a to get 7. I hope this helps :)
X - 3 × 10 -13 = x - 30 -13 = x - 43