QUESTION 1

Mathematics

1 answer:

siniylev [52]3 years ago

3 0

Answer:

Step-by-step explanation:

Given that the adult dosage = 15 mg/day.

1. The pediatric dosage for a child weighing 52 pounds can be determined by;

Pediatric Dosage = (Child weight divided by 150 lbs.) x Adult Dose

= $\frac{52}{150}$ x 15 mg/day

= 5.2 mg/day

The pediatric dosage of the medication for a child weighing 52 pounds is 5.2 mg per day.

2. The medication can be consume by either an adult or a pediatric at a measured quantity. If an adult takes 15 mg of the medication per day, then any child whose weight is 52 pounds can take a maximum quantity of 5.2 mg of the medication per day. This implies that a child of the measured weight should not take more than 5.2 mg of the medication per day, and probably not at once.

The dosage of the medication for a pediatric can be determined by;

Pediatric Dosage = (Child weight divided by 150 lbs.) x Adult Dose

That is, once the weight of a child is determined, the dosage can be calculated.

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A warehouse employs 22 workers on first shift and 18 workers on second shift. Eight workers are chosen at random to be interview

bogdanovich [222]

Answer:

The probability is 0.0042

Step-by-step explanation:

The probability is the division between the number of ways in which the eight workers are chosen from the first shift and the total number of ways in which they can select the eight workers.

So, the number of ways in which the eight workers are chosen from the first shift is calculate using the following equation:

$nCk=\frac{n!}{k!(n-k)!}$

Where nCk give as the number of ways in which we can select k element from a group of n elements.

Then replacing k by the eight workers that are going to do the interview and n by the 22 workers from the first shift we get:

$22C8=\frac{22!}{8!(22-8)!}= 319,770$

So there are 319,770 ways to select eighth workers and all of them are first shift workers.

At the same way, we can calculate the total number of ways in which they can select the eight workers. Replacing n by 40 because this is the sum of 22 workers of the first shift and 18 workers of the second shift, we get:

$40C8=\frac{40!}{8!(40-8)!}= 76,904,685$