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zysi [14]
2 years ago
14

The value of the power is

Mathematics
2 answers:
cricket20 [7]2 years ago
7 0

Answer:

See below ~

Step-by-step explanation:

Power in repeated multiplication form is : 4 x 4 x 4 x 4

Value of the power : 16 x 16 = 256

tiny-mole [99]2 years ago
3 0

Answer:

Is 4

4

Step-by-step explanation:

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A flower pot has 6 sides that are all tha same length. Each side measures x -6 units, the bases perimeter is 78 units. What is t
lakkis [162]

Answer:

The value of x is 19\ units

Step-by-step explanation:

we know that

The perimeter of flower pot is equal to

P=6(x-6)

we have

P=78\ units

substitute and solve for x

78=6(x-6)

13=(x-6)

x=13+6=19\ units

7 0
3 years ago
I need help out please quiz
sleet_krkn [62]

Answer:

SSS

Step-by-step explanation:

if 2 sides are equal the third side is also equal

3 0
3 years ago
What is 2y + x (3y) = - 15
enot [183]

Answer:

x=\frac{-2y-15}{3y}

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4 0
4 years ago
An acute angle θ is in a right triangle with sin θ = one half. What is the value of cot θ?
MrMuchimi

Answer:

  √3

Step-by-step explanation:

  cot²(θ) = csc²(θ) -1 . . . . . a relevant identity

  = 1/sin²(θ) -1

  = (1/(1/2))² -1 = 2² -1 = 3

Then ...

  cot(θ) = √3 . . . . . . . . take the square root

7 0
3 years ago
Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man
Bess [88]

Answer:

on \: this \: farm \: there \: are \to \\  \underline{ \boxed{17 \: pigs }}\:  \\  and \\  \underline{ \boxed{28 \:chickens}}

Step-by-step explanation:

\\  \underline{ \boxed{solution \: to \: question \:  \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\  hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\  while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs  = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \:  of \:  equations \: \\   to  \: describe  \: the  \: situation \: is \to \\ \\  p + c = 45 \\ 4p + 2c = 124 \\  \\  \\ \underline{ \boxed{solution \: to \: question \:  \boxed{B }}} \\  \\  \\ we \: could \: apply \: any \: of \: the \: simultanious \\  principles \to \\ here : am \: appling \: the \: elimination \: method   \to \\ p + c = 45 \\ 4p + 2c = 124  \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124  \\ hence \to \\   - \frac{4p + 4c = 180}{4p + 2c = 124}  \\next \to \\   2c = 56 \\ c =  \frac{56}{2}  \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\  \boxed{p = 17}

6 0
3 years ago
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