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igomit [66]
3 years ago
15

Factor 4x^2-4x-8 Please help

Mathematics
2 answers:
gavmur [86]3 years ago
5 0

Answer:

4x² - 4x - 8 can be factored into 4(x - 2)(x + 1)

Step-by-step explanation:

First, we can factor out 4, as all terms are divisible by that:

4x² - 4x - 8

= 4(x² - x - 2)

Now we need to find two numbers that are are factors of -2, but add up to -1.  -2 and 1 meet that condition, so let's split the middle term into those coefficients:

=4(x² + x - 2x - 2)

= 4( x(x + 1) - 2(x - 1) )

= 4(x - 2)(x + 1)

Westkost [7]3 years ago
5 0

Answer:

4(x+1)x(x-2)

Step-by-step explanation:

Step 1: factor it

4(x^2-x-2)

Step 2: re write the expression and make -x as a difference

4(x^2+x-2x-2)

Step 3: factor out x from the expression

4(x *(1+1)-2(x+1))

Step 4: factor out x+1 from the expression

4(x+1) x (x-2)

Das it hope you have a good day lol

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Juli2301 [7.4K]

Answer:

D

Step-by-step explanation:

"six plus two" = (6+2)

"nine plus three" = (9 + 3)

"six plus two" is less than "nine plus three"

= (6+2) < (9+3)   (Answer D)

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4 years ago
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Whats the product of 3 2/3 and 14 2/5
vodka [1.7K]
11 1/5 Also, if u need in decimal it is 11.2
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Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write
Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

  • Use double point formula and simplify it to get two eqaution.
  • Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1} (x - x1)

~ Keep all values.

(y  + 4) =  \frac{11 + 4}{2 + 1} (x + 1)

~ Simplify it.

y + 4 =  \frac{15}{3} (x + 1)

y + 4 = 5x + 5

5x - y + 1 = 0

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1}(x - x1)

~ Keep all values.

(y - 1) =  \frac{10 - 1}{4 - 1} (x - 1)

~ Simplify it.

y - 1 = 3 x - 3

3x - y - 2 = 0

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

m1 =  \frac{ - coeff. \: of \: x}{coeff \: of \: y}

m1 =  \frac{ - 5}{ - 1}

Therefore, m1 = 5

Slope of second equation.

m2 =  \frac{ - coeff \: .of \: x}{coeff \: .of \: y}

m2 =   \frac{ - 3}{ - 1}

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
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G is equal to 36. Hope I helped.
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Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha
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The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
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P = (-2,6)
P ' = (-4,-10) 

The answer is -10 because your teacher just wants the y coordinate of point P'
4 0
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