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3 years ago

Factor 4x^2-4x-8 Please help

Mathematics

2 answers:

gavmur [86]3 years ago

5 0

Answer:

4x² - 4x - 8 can be factored into 4(x - 2)(x + 1)

Step-by-step explanation:

First, we can factor out 4, as all terms are divisible by that:

4x² - 4x - 8

= 4(x² - x - 2)

Now we need to find two numbers that are are factors of -2, but add up to -1. -2 and 1 meet that condition, so let's split the middle term into those coefficients:

=4(x² + x - 2x - 2)

= 4( x(x + 1) - 2(x - 1) )

= 4(x - 2)(x + 1)

Westkost [7]3 years ago

5 0

Answer:

4(x+1)x(x-2)

Step-by-step explanation:

Step 1: factor it

4(x^2-x-2)

Step 2: re write the expression and make -x as a difference

4(x^2+x-2x-2)

Step 3: factor out x from the expression

4(x *(1+1)-2(x+1))

Step 4: factor out x+1 from the expression

4(x+1) x (x-2)

Das it hope you have a good day lol

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2 years ago

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3 years ago

2. Find the cosine function that is represented in the graph.

Diano4ka-milaya [45]

Answer:

$f(x) = cos(x - \frac{\pi }{4} ) -1$

Step-by-step explanation:

In this graph, we have the coordinate point ( $\frac{\pi }{4} , 0$ ). Without translations, cos(0) = 0, which means that the graph is shifted to the right by $\frac{\pi }{4}$ . We also know that the graph is shifted down by 1 because we have the point

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