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3 years ago

Factor 4x^2-4x-8 Please help

Mathematics

2 answers:

gavmur [86]3 years ago

5 0

Answer:

4x² - 4x - 8 can be factored into 4(x - 2)(x + 1)

Step-by-step explanation:

First, we can factor out 4, as all terms are divisible by that:

4x² - 4x - 8

= 4(x² - x - 2)

Now we need to find two numbers that are are factors of -2, but add up to -1. -2 and 1 meet that condition, so let's split the middle term into those coefficients:

=4(x² + x - 2x - 2)

= 4( x(x + 1) - 2(x - 1) )

= 4(x - 2)(x + 1)

Westkost [7]3 years ago

5 0

Answer:

4(x+1)x(x-2)

Step-by-step explanation:

Step 1: factor it

4(x^2-x-2)

Step 2: re write the expression and make -x as a difference

4(x^2+x-2x-2)

Step 3: factor out x from the expression

4(x *(1+1)-2(x+1))

Step 4: factor out x+1 from the expression

4(x+1) x (x-2)

Das it hope you have a good day lol

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6.15 divided by 31 rounded

nikdorinn [45]

It would be (rounded) 5
Because
31 / 6.15 = 5.04065

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3 years ago

Estimate:________ 74,529 - 38453

kiruha [24]

Answer:

35,000?

Step-by-step explanation:

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3 years ago

The graph of f(x) =(square root of "x") is reflected across the x-axis and then across the y-axis to create the graph of functio

vesna_86 [32]

Analysis:

1) The graph of function f(x) = √x is on the first quadrant, because the domain is x ≥ 0 and the range is y ≥ 0

2) The first transformation, i.e. the reflection of f(x) over the x axis, leaves the function on the fourth quadrant, because the new image is y = - √x.

3) The second transformation, i.e. the reflection of y = - √x over the y-axis, leaves the function on the third quadrant, because the final image is - √(-x). This is, g(x) = - √(-x).

From that you have, for g(x):

* Domain: negative x-axis ( -x ≥ 0 => x ≤ 0)

* Range: negative y-axis ( - √(-x) ≤ 0 or y ≤ 0).

Answers:

Now let's examine the statements:

A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0

B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0

C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.

D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.

E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.

F)The range of g(x) is all values less than or equal to 0. TRUE: it was proved above.

4 0

4 years ago

Read 2 more answers

In a large lecture class, the professor announced that the scores on a recent exam were normally distributed with a range from 5

iVinArrow [24]

Answer:

The standard deviation of the scores on a recent exam is 6.

The sample size required is 25.

Step-by-step explanation:

Let X = scores of students on a recent exam.

It is provided that the random variable X is normally distributed.

According to the Empirical rule, 99.7% of the normal distribution is contained in the range, μ ± 3σ.

That is, P (μ - 3σ < X < μ + 3σ) = 0.997.

It is provided that the scores on a recent exam were normally distributed with a range from 51 to 87.

This implies that:

P (51 < X < 87) = 0.997

So,

μ - 3σ = 51...(i)

μ + 3σ = 87...(ii)

Subtract (i) and (ii) to compute the value of σ as follows:

μ - 3σ = 51

(-)μ + (-)3σ = (-)87

______________

-6σ = -36

σ = 6

Thus, the standard deviation of the scores on a recent exam is 6.

The (1 - α)% confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

The margin of error of this interval is:

$MOE = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Given:

MOE = 2

σ = 6

Confidence level = 90%

Compute the z-score for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a z-table.

Compute the sample required as follows:

$MOE = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\2=1.645\times \frac{6}{\sqrt{n}}\\n=(\frac{1.645\times 6}{2})^{2}\\n=24.354225\\n\approx 25$

Thus, the sample size required is 25.

4 0

3 years ago

The function f(x) = −x2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in

lisabon 2012 [21]

First of all, the root is $5$ , since

$-5^2-5\cdot 5 + 50 = -25-25+50=0$

Then, since the $x$ represents the horizontal distance, and $f(x)$ the height, we can read $f(5)=0$ as "the height is zero when the diver is $5$ feet away from the board.

So, the answer is D.

3 0

3 years ago