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gayaneshka [121]
3 years ago
15

HELPPP 3p-4-8p<-19 i need the steps as well

Mathematics
1 answer:
sergey [27]3 years ago
7 0

9514 1404 393

Answer:

  p > 3

Step-by-step explanation:

  3p -4 -8p < -19 . . . . . . given

  -5p -4 < - 19 . . . . . . . . collect terms

  -5p < -15 . . . . . . . . . . . add 4

  p > 3 . . . . . . . . . . . . . . divide by -5 (reverses the inequality symbol)

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Simplify this radical. <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%7D%2084" id="TexFormula1" title="\sqrt{} 84" alt="\sqrt{} 84
igor_vitrenko [27]

Answer:

2√21

Step-by-step explanation:

\sqrt{84}\\\\\mathrm{Prime\:factorization\:of\:}84:\quad 2^2\times\:3\times\:7\\=\sqrt{2^2\times\:3\times \:7}\\\\=\sqrt{2^2}\sqrt{3\times\:7}\\\\\sqrt{2^2}=2\\\\=2\sqrt{3\times\:7}\\\\=2\sqrt{21}

5 0
3 years ago
What is the square root of 28x to the third power y to the third power
Colt1911 [192]

Hello!

√28x³y³ is equal to 2xy\sqrt{7xy}

We can find this solution through the following steps.

  1. Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
  2. We then can rewrite 4 as 2² in our equation, leaving us with \sqrt{2^{2}*7*(x^{2}x)*y^{2}y }
  3. We will then move our x and 7, and rewrite 2^{2}*x^{2}* y^{2} as (2xy)^{2}
  4. We can then pull the terms from the radical leaving us with 2xy\sqrt{7xy}
6 0
4 years ago
What is the quotient (x^3+8)/(x+2)
Citrus2011 [14]

Answer:

Step-by-step explanation:

The easiest way to do this is by using synthetic division (I really hope you know what I'm talking about!)

If the factor is x + 2 = 0, then the solution or the root is x = -2.  We will put -2 outside the "box" and the coefficients from the terms of the polynomial inside the "box":

-2|   1    0    0    8

Bring down the first number and multiply it by the -2.  Put the product up under the first 0 and add:

-2|   1    0    0    8

           -2

      1   -2  

Now multiply the -2 by the -2, put the product up under the next 0 and add:

-2|   1    0    0    8

           -2    4

      1    -2    4

Now multiply the 4 by the -2, put the product up under the 8 and add:

-2|   1    0    0    8

           -2   4    -8

     1    -2   4    0

Those bold numbers are the coefficients to the quotient, which is another polynomial, but is one degree less than the one you started with:

x² - 2x + 4 = 0

Since there is no remainder, then x = -2 is a zero of x³ + 8, and (x + 2) is a factor.

There is a whole world of stuff to learn about quadratics!!

4 0
3 years ago
The zeroes of the function are . of the zeroes have a multiplicity of 2.
NISA [10]

Answer:

The three roots have a multiplicity of 2

Step-by-step explanation:

The zeros of the function refers to those points on the x-axis on which the curve passes through

These are the points -2,0 and 4

Now we want to determine which of these points has a multiplicity of 2?

The correct answer is that all have a multiplicity of 2 since 2 can be factored out

2(-1) , 2(0) and 2(2)

7 0
4 years ago
Solve this triangle round to the nearest tenth where necessary
Fynjy0 [20]

Answer:

J =51

Step-by-step explanation:

Your welcome! Have a great day!

8 0
3 years ago
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