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2 years ago

10

Which expression is equivalent to 8(2a)? 8(2 + a) 8 + 2a 8(a + a) a + 10

2 answers:

Nadusha1986 [10]2 years ago

4 0

Answer:

8(2+a) is the answer that you need there really is not much thought to it

Inga [223]2 years ago

4 0

The first one is correct!

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Evaluate the function.<br><br> g(x)=10x+3<br><br> g(19.6)=

Zolol [24]

Answer:

199

Step-by-step explanation:

plug in x=19.6, then

g(19.6) = 10 * 19.6 +3= 199

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3 years ago

660 miles on 20 gallons or 850 miles on 25 gallons which is greater

storchak [24]

The second. Hope that helps.

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1 year ago

What is the product of 60?

Rzqust [24]

We divide 60 by 2 as many times as possible to get 60 = 15 x 2 x 2. 2 is a prime number so we don't need to break the 2's down any more. Instead we break 15 down. 15 doesn't divide by 2 so we try the next prime number: 3 Divide 15 by 3 to get 15 = 5 x 3, and so 60 = 5 x 3 x 2 x 2.

8 0

2 years ago

Read 2 more answers

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

The ratio of the weight of Jennifer to that of her friend Laura is 6:11. Laura goes on a diet and loses 12kg and now the ratio o

Inessa05 [86]

Answer:

21kg

Step-by-step explanation:

We will do this.

11x - 12 = 7x

11x - 4x = 7x

4x = 12

4x/4 = 12/4

x = 3

3 x 7 = 21

Laura weighs 21 kg.

3 0

2 years ago