Please help? <br><br> (No link <3)

Change the fraction w-3/w+5 into an equivalent fraction with the denominator w2 + w – 20.

viktelen [127]

ANSWER

$\frac{ {w}^{2} - 7w + 12}{ {w}^{2} + w - 20 }$

EXPLANATION

The given fraction is,

$\frac{w - 3}{w + 5}$

To get an equivalent fraction, we multiply both the numerator and the denominator by the same quantity that will give us

w²+w-20

in the denominator.

This implies that,

$\frac{w - 3}{w + 5} = \frac{(w - 3)(w - 4)}{(w + 5)(w - 4)}$

We multiply out the numerators and denominators using the distributive property to obtain,

$\frac{w - 3}{w + 5} = \frac{ {w}^{2} - 4w - 3w + 12}{ {w}^{2} - 4w + 5w - 20 }$

This simplifies to

$\frac{w - 3}{w + 5} = \frac{ {w}^{2} - 7w + 12}{ {w}^{2} + w - 20 }$

5 0

3 years ago

How many quarts does the faucet leak per hour?

Citrus2011 [14]

Answer) -5/2 quarts per hour
Work) There are 60 minutes in an hour and the faucet is losing water every 15 minutes so divide 60/15 and you get 4, next you take the 5/8 and times it by the 4 and you get -5/2

6 0

3 years ago

. The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to nd

Blababa [14]

The question is:

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find a second solution y2(x) of the homogeneous equation

x²y'' - 7xy' + 16y = 0; y1 = x^4

Answer:

The second solution y2 is

A(x^4)lnx

Step-by-step explanation:

Given the homogeneous differential equation

x²y'' - 7xy' + 16y = 0

And a solution: y1 = x^4

We need to find a second solution y2 using the method of reduction of order.

Let y2 = uy1

=> y2 = ux^4

Since y2 is also a solution to the differential equation, it also satisfies it.

Differentiate y2 twice in succession with respect to x, to obtain y2' and y2'' and substitute the resulting values into the original differential equation.

y2' = u'. x^4 + u. 4x³

y2'' = u''. x^4 + u'. 4x³ + u'. 4x³ + u. 12x²

= u''. x^4 + u'. 8x³ + u. 12x²

Now, using these values in the original equation,

x²(u''. x^4 + u'. 8x³ + u. 12x²) - 7x(u'. x^4 + u. 4x³)+ 16(ux^4) = 0

x^6u'' + 8x^5u' + 12x^4u - 7x^5u' - 28x^4u + 16x^4u = 0

x^6u'' + x^5u' = 0

xu'' = -u'

Let w = u'

Then w' = u''

So

xw' = -w

w'/w = -1/x

Integrating both sides

lnw = -lnx + C

w = Ae^(-lnx) (where A = e^C)

w = A/x

But w = u'

So,

u' = A/x

Integrating this

u = Alnx

Since

y2 = uy1

We have

y2 = (Alnx)x^4 = (Ax^4)lnx

Therefore, the second solution y2 is

A(x^4)lnx

6 0

3 years ago

Help me out please. Correct answers only

Sergio [31]

Answer:

c=39

Step-by-step explanation:

4+2=6

To remove square root you have to square everything making the 6 a 36 and then add 3. At the end it is a 39.

8 0

3 years ago

Read 2 more answers

Describe how adding and subtracting mixed numbers can help you with recipes.

andrey2020 [161]

Because there's times when u need to double for instance a cup so u have to add one morecup

3 0

3 years ago

Read 2 more answers

Please help? (No link <3)