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EleoNora [17]
3 years ago
14

How can I simplify these?

Mathematics
1 answer:
Schach [20]3 years ago
4 0

Answer:

\large\boxed{343=7\sqrt7}\\\boxed{10\sqrt{96}=40\sqrt6}

Step-by-step explanation:

343=7^3=7^2\cdot7\\\\\sqrt{343}=\sqrt{7^2\cdot7}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{7^2}\cdot\sqrt7\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=7\sqrt7\\=====================\\\\96=16\cdot6\\\\10\sqrt{96}=10\sqrt{16\cdot6}=10\sqrt{16}\cdot\sqrt6=(10)(4)\sqrt6=40\sqrt6

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The expressions that are equivalent when m = 1 and m = 4 is;

Option B: 3m + 4 and m + 4 + 2m

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A) 5m - 3 and 2m + 5 + m

B) 3m + 4 and m + 4 + 2m

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D) 5m + 3 and 4m + 2 + 2m

For option B; 3m + 4 and m + 4 + 2m

Let's put m = 1

3(1) + 4 = 7

Also, 1 + 4 + 2(1) = 7

Similarly, let us put 4 for m to get;

3(4) + 4 = 16

Also, 4 + 4 + 2(4) = 16

In both cases, the expressions are equivalent and as such option B is the right one.

Read more about algebra simplifications at; brainly.com/question/4344214

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3 years ago
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