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iris [78.8K]
3 years ago
11

11. Find the perimeter and area of the figure shown.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer:

Perimeter = 16 units

Area = 15 squared units

Step-by-step explanation:

ABCD is a rectangle.

It's length l = 5 units

and width w = 3 units

Perimeter of ABCD = 2(l + w) = 2(5 + 3) = 2*8 = 16 units

Area of ABCD = 5*3 = 15 squared units.

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Suppose a triangle has two sides of length 3and 4 and that the angle between these two sides is 60. What is the length of the th
tangare [24]

9514 1404 393

Answer:

  A.  √13

Step-by-step explanation:

You can make an educated guess and come to the right conclusion.

The triangle is nearly an equilateral triangle. A triangle with two sides 3 and an angle of 60° would have a third side of 3. A triangle with two sides of 4 and an angle of 60° would have a third side of 4.

So, the third side must be between 3 and 4. Here is an evaluation of the answer choices:

__

A -- between 3 and 4, the correct choice

B -- 3, too short

C -- 1.73, too short

D -- more than 4, too long

__

The question can be answered using your triangle solver app on your calculator, or using the Law of Cosines.

  c = √(a^2 +b^2 -2ab·cos(C))

  c = √(3^2 +4^2 -2·3·4·(1/2)) = √(9 +16 -12)

  c = √13 . . . . . length of the side opposite the 60° angle

5 0
3 years ago
What is the nearest ten thousand rounded to 836527
motikmotik

Answer:

837,000

Step-by-step explanation:

If a number is above 5 round up, if it is below 4 round down

3 0
3 years ago
Read 2 more answers
Help please. !!! Practical math
Neko [114]
Put all numbers in order from least to greatest
median is the middle number
so
5,9,10,11,12,14
median = ( 10+11)/2 = 10.5

answer
C. 10.5
3 0
3 years ago
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What is the difference between –4 and 6?
Andrew [12]
The difference between them is 10

-4 - 6 = -10, however since it is only asking for the <em>difference, </em>your answer would be 10.
5 0
3 years ago
Can someone please help me lol ​
Whitepunk [10]

Answer:

C

Step-by-step explanation:

3 0
2 years ago
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