What figure is the question talking about lmk ?
Answer:
The 3 cyclists will meet at the starting point again after 150 minutes.
Step-by-step explanation:
Since they start at the same point but then take different times to each route, then to find the first time they will each meet at the starting point, we have to find the lowest common multiple (LCM).
Let's use prime factorization to get it.
Prime factorization of 10 = 2 × 5
Prime factorization of 15 = 3 × 5
Prime factorization of 25 = 5 × 5
Thus,super set = 2, 3, 5, 5
Thus,LCM = 2 × 3 × 5 × 5 = 150
Thus,the 3 cyclists will meet at the starting point again after 150 minutes.
Step-by-step explanation:
first do and there come some answer and take them eqn (i) and in 2nd put first eqn value and there will answer come
Given:
A(3,0)
B(1,-2)
C(3,-5)
D(7,-1)
1) reflect across x=-4
essentially calculate the difference between the x=-4 line and Px and "add" it in the other direction to x=-4
A(-4-(3-(-4)),0)=A(-11,0)
B(-4-(1-(-4)),-2)=B(-9,-2)
C(-4-(3-(-4),-5))=C(11,-5)
D(-4-(7-(-4)),-1)=D(-15,-1)
2) translate (x,y)->(x-6,y+8)
A(-3,8)
B(-5,6)
C(-3,3)
D(1,7)
3) clockwise 90° rotation around (0,0), flip the x&y coordinates and then decide the signs they should have based on the quadrant they should be in
A(0,-3)
B(-2,-1)
C(-5,-3)
D(-1,-7)
D) Dilation at (0,0) with scale 2/3, essentially multiply all coordinates with the scale, the simple case of dilation, because the center point is at the origin (0,0)
A((2/3)*3,(2/3)*0)=A(2,0)
B((2/3)*1,(2/3)*-2)=B(2/3,-4/3)
C((2/3)*3,(2/3)*-5)=C(2,-10/3)
D((2/3)*7,(2/3)*-1)=D(14/3,-2/3)
