(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
Answer:
let alpha be x and beta be y
Step-by-step explanation:
x+y= -b/a
x+y=-1/6
and xy= c/a
xy= -1/3
according to question
1/x+1/y -xy =(x+y)/xy-xy
(-1/6)/(-1/3)-(-1/3)
1/2+1/3
the answer is 5/6
If she wanted to buy new utensils she could buy 108 spoons and 261 knifes then she would have 2,006 forks, spoons, and knifes. Or she could donate 261 forks and 153 spoons and have 1,745 of each utensils.
