<img src="https://tex.z-dn.net/?f=%5Ccolor%7Bred%7D%7B%5Ctt%20%7BIn%20%5C%3A%20%20%CE%94%20%5C%3A%20%20ABC%2C%20%E2%88%A0B%3D90%

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2 years ago

7

2C%20AB%20%3D%208%20%5C%3A%20%20cm%20%20%5C%3A%20and%20%5C%3A%20%20BC%20%3D%206%20%20%5C%3A%20cm.%20Find%20%5C%3A%20%20the%20%5C%3A%20%20length%20%5C%3A%20%20of%20%5C%3A%20%20AC.%20%7D%7D" id="TexFormula1" title="\color{red}{\tt {In \: Δ \: ABC, ∠B=90, AB = 8 \: cm \: and \: BC = 6 \: cm. Find \: the \: length \: of \: AC. }}" alt="\color{red}{\tt {In \: Δ \: ABC, ∠B=90, AB = 8 \: cm \: and \: BC = 6 \: cm. Find \: the \: length \: of \: AC. }}" align="absmiddle" class="latex-formula">

2 answers:

Sliva [168]2 years ago

6 0

Answer:

Solution given;

<B=90

so

AB=b=8cm

BC=p=6cm

AC=h=?

by using Pythagoras law

h²=p²+b²

h=√{6²+8²)

h=10cm

so

<u>length</u><u> </u><u>of</u><u> </u><u>AC</u><u>=</u><u>1</u><u>0</u><u>c</u><u>m</u><u>.</u>

makkiz [27]2 years ago

5 0

Use Pythagoras theorem

Hypotenuse²=Base²+ Height ²

H²=(8)²+(6)²

H²=64+36

H²= 910

H²=10√91 cm Solution

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