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Alenkinab [10]
3 years ago
9

What is the slope of the line of (1,0) and (-1,-3)

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Slope formula: m = \frac{(y2-y1)}{(x2-x1)} (Knowing that m represents the slope)

Substitute (1,0) for (x1,y1), and (-1,-3) for (x2,y2)

Slope of the line of (1,0) and (-1,-3) is:

m = \frac{(-3-0)}{(-1-1)} = \frac{-3}{-2} = \frac{3}{2}  

(Simplify)

Slope of the line of (1,0) and (-1,-3) is \frac{3}{2}

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Which best expression is the best estimate of the product of 7/8 and 8 1/10
Mars2501 [29]

Answer:

D. 1x8

Step-by-step explanation:

7/8 rounded is 1. And 8 and 1/10 rounder is 8, so therefore your answer is 1x8.

hope this helps! :)

7 0
3 years ago
What is the y-intercept of the polynomial f(x)f(x) defined below? Write the y-value only. f(x)=-4x^2+x^5+10x^3+5x+8x^4
Debora [2.8K]

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Step-by-step explanation:

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3 0
2 years ago
WILL MARK BRAINIEST FOR FIRST PERSON TO ANSWER WITH THE STEPS
kondaur [170]

Answer:

  a. 1.2 ohms

  b. 6 ohms

Step-by-step explanation:

As with any problem involving evaluation of a formula, substitute the given values for the corresponding variables and do the arithmetic.

a.

  R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{2}+\dfrac{1}{3}}=\dfrac{1}{\left(\dfrac{5}{6}\right)}=\boxed{\dfrac{6}{5}=1.2}

__

b.

  R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{10}+\dfrac{1}{15}}=\dfrac{1}{\left(\dfrac{5}{30}\right)}=\dfrac{30}{5}=\boxed{6}

_____

<em>Comment on these problems</em>

You will notice that the values in part (b) are 5 times those in part (a). So, it is no surprise that the answer in part (b) is 5 times the answer in part (a).

7 0
3 years ago
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nirvana33 [79]

Answer:

c and g

Step-by-step explanation:

6 0
3 years ago
Explain why ΔADB ≅ ΔCDB. List the other corresponding parts.
anygoal [31]

Answer:

Therefore the Correct option is First one

SAS, ∠A ≅ ∠C,  AB ≅ CB , ∠ABD ≅ ∠CBD .

Step-by-step explanation:

Given:

∠BDA ≅ ∠BDC

AD ≅ CD

TO Prove

ΔADB ≅ ΔCDB

Proof:

In  ΔADB  and ΔCDB  

AD ≅ CD               ....……….{Given}

∠BDA ≅ ∠BDC     …………..{Given}

BD ≅ BD               ....……….{Reflexive Property}

ΔADB ≅ ΔCDB  ….{By Side-Angle-Side Congruence Postulate}

∴ ∠A ≅ ∠C  ......{Corresponding Parts of Congruent Triangle are Congruent}

  AB ≅ CB  ......{Corresponding Parts of Congruent Triangle are Congruent}

∠ABD ≅ ∠CBD {Corresponding Parts of Congruent Triangle are Congruent}

3 0
3 years ago
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