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alisha [4.7K]
3 years ago
12

If the radius of circle A is 6 units, calculate the area of the shaded region...

Mathematics
1 answer:
meriva3 years ago
4 0

The formula of an area of a triangle:

A_{\triangle}=\dfrac{base\cdot height}{2}

We have:

\triangle_{FDE}:\ base=height=1\\\triangle_{GDH}:\ base=height=9

substitute:

A_{\triangle_{FDE}}=\dfrac{1\cdot1}{2}=0.5\\\\A_{\triangle_{GDH}}=\dfrac{9\cdot9}{2}=40.5

The formula of an area of a circle:

A_O=\pi r^2

We have r=6

Substitute:

A_O=\pi\cdot6^2=36\pi\approx36\cdot3.14=113.04

The area of the shaded region

A=A_O-(A_{\triangle_{FDE}}+A_{\triangle_{GDH}})\\\\A=113.04-(0.5+40.5)=113.04-41=72.04\ u^2

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8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

<h3>How to solve the trigonometry</h3>

8. We have the angle to be 20 degrees

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sin 20 = \frac{x}{23}

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sin 20 × 23 = x

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9. The angle of elevation is 37. 3 degrees

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Using the sine ratio

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cross multiply

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The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

For side a, we use the Pythagorean theorem

c^2 = a^2 + b^2

85^2 = a^2 + 67^2

a = \sqrt{89^2-67^2}

a = \sqrt{3432}

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

\frac{59}{sin A } = \frac{85}{sin 90}

cross multiply

sin A × 85 = sin 90 × 59

make sin A subject of formula

sin A = \frac{59}{85}

sin A = 0. 6941

A = sin^-^1(0. 6941)

A = 44°

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cross multiply

sin B × 85 = sin 90 × 67

make sin b subject of formula

sin B = \frac{67}{85}

sin B = 0. 7882

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4. To find the sides, we use the sine rule;

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Cross multiply

sin 56. 6 × c = sin 90 × 74

make 'c' subject of formula

c = \frac{74}{0. 8348}

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

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b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}

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cross multiply

sin B = \frac{40. 99}{74. 0}

B = sin^-^1(0. 5539)

B = 34°

Learn more about trigonometric identity here:

brainly.com/question/7331447

#SPJ1

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