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3 years ago

HI i'm giving brainiest for the best answer!

Mathematics

2 answers:

Anika [276]3 years ago

7 0

Answer:

p(1/4)40

Step-by-step explanation:

hope this helps^^

blsea [12.9K]3 years ago

6 0

The answer is
p (1/4) 40

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vredina [299]

Answer:

Mag kape ka nalang wag kana mag module

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3 years ago

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What is 3.9 times 0.5 plus 4 5/6 divided by 3 3/7

topjm [15]

I used a math calculator to evaluate this expression you just plug it in and it gives you the answer with all the steps. use the app FX math junior, but this is the answer ; 2419/720=3.3597

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3 years ago

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Two dice are rolled. Use the complement rule to find that the probability that the sum of the dice is less than 10.

Katarina [22]

Answer:

$\dfrac{5}{6}$

Step-by-step explanation:

When two dice are rolled, the sample space is

$\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}$

In total, 36 outcomes

First, find the probability that the sum is 10 or greater:

All favorable outcomes

10: $(4,6),\ (5,5),\ (6,4)$

11: $(5,6),\ (6,5)$

12: $(6,6)$

In total, 6 outcomes.

The probability that the sum is 10 or greater is

$P(A)=\dfrac{6}{36}=\dfrac{1}{6}$

Use the complement rule to find that the probability that the sum of the dice is less than 10:

$P(A^C)=1-P(A)=1-\dfrac{1}{6}=\dfrac{5}{6}$

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3 years ago

Complete the table below.

Drupady [299]

Answer:

A (in millions) B (in millions) C D E F G

Total Market Value Total Shares Issued Value Per Share Amount Invested Charge D minus E Shares Purchased

$47 2 $

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3,750

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$25 4 $

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$4,000 $250 $

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Step-by-step explanation:

Those are the answers, copy and pastes- good luck though : ))

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3 years ago

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A factory produces car tires. The number of miles each tire lasts before it completely wares out follows a normal distribution w

qwelly [4]

Answer: 0.0668073

Step-by-step explanation:

Given : The number of miles each tire lasts before it completely wares out follows a normal distribution with mean μ = 50,000 miles and standard deviation σ = 8,000 miles.

Let x be the random variable that represents the number of miles each tire lasts.

z-score : $\dfrac{x-\mu}{\sigma}$

For x= 62,000

$z=\dfrac{62000-50000}{8000}=1.5$

By using the standard z-value table , the probability for a randomly selected tire to last for at least 62,000 miles will be :_

$P(x\geq62000)=P(z\geq1.5)=1-P(z$

Hence, the probability for a randomly selected tire to last for at least 62,000 miles = 0.0668073

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3 years ago