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goldenfox [79]
3 years ago
6

What is the area of the circle below? Use π = 3.14 to solve. Round your answer to the nearest hundredth.

Mathematics
2 answers:
Alexxx [7]3 years ago
8 0

Answer:

A = 803.84 ft

Step-by-step explanation:

The area of a circle formula is A = πr²

We are given the radius, which is r = 16 ft.

So, all we have to do is substitute numbers:

A = (3.14)(16²)

A = (3.14)(256)

A = 803.84 ft

dezoksy [38]3 years ago
3 0

Answer:

803.84 ft ²

:)

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Two number differ by 3 The sum of their reciporcal is 7/10 find tge numbers
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The numbers are 5 and 2.

Reciprocals: 5- 5/10
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(2/10)+(5/10)= 7/10
5-2= 3
 
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The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

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