If A=Aiden’s weight and J=Jacob’s weight, so A=J-39 or J=A+39.
J>100 so A+39>100, and A>61 pounds.
A+J>>61+100, A+J>>161. Or, A+J=2J-39=2A+39>161.
If A=62, J=101, so A+J=163 pounds.
Therefore we can say their combined weights will 161 pounds, and 163 pounds would be a typical weight.
Answer c I haven’t done this in awhile but I’m sure it’s c
A is

absolute value is always positive, the minus sign vanishes (it literally means "how far away from zero" something is. distance can't be negative.)
B ist just 18
The area of the sector, when the measure of the central angle is in radians, can be solved using this equation:
A = (n/2) r²
From the given values,
A = (π/6/2) (10²)
A = 25π/6 = 26.18 in²
Therefore, the area of the sector with the central angle measuring π/6 with the radius of the circle 10 inches is 26.18 in²