First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
Answer:
Step-by-step explanation:
Sum of cubes is a^3+b^3=(a+b)(a^2-ab+b^2)
64x^3+1
(4x+1)(16x^2-4x+1)
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Answer:
D. 3
Step-by-step explanation:
If the ratio of their sides is 4:1, and if PQ=12 inches, then Ab=12/4=3 inches.
Answer:
x = -1
Step-by-step explanation:
5x + 5 = 0
Subtract 5 from each side
5x+5-5 = 0-5
5x = -5
Divide by 5 on each side
5x/5 = -5/5
x = -1