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Neporo4naja [7]
3 years ago
5

Please help me solve this guys

Mathematics
1 answer:
NeTakaya3 years ago
4 0

Answer:

Factored Form: y=(x+1) ( x+3)y=(x+1)(x+3)

X-intercepts: (-1,0), (-3,0)(−1,0),(−3,0)

Axis of Symmetry: x= -2x=−2

Vertex: (-2,-1)(−2,−1)

Domain: (\begin{gathered}(-\infty , \infty ), ( x | x ER)\\\end{gathered}

(−∞,∞),(x∣xER)

Range: y > =-1y>=−1

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The pickerington girls track team ran a 4 by 100 meter relay in 48.9 seconds. If four girls ran the race how fast did each girl
Oduvanchick [21]
48.9 / 4 = 12.225
distance = 100m
time = 12.225 sec
v = d/t
The answer is 8.1799
5 0
3 years ago
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The sun produces 3.8x10^27 joules of energy per second. How much energy is produced in a year? (Note: a year is approximately 31
Slav-nsk [51]
About 1.204972095x10^20 joules in a year
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3 years ago
If m<1=6x+50 and m<2=4x+40 find x
Pepsi [2]
\text{Adjacent angles on a straight line sum up to 180} \textdegree

\text{Therefore }\measuredangle 1 + \measuredangle 2 = 180 \textdegree

\text {Since } \measuredangle 1 = 6x+50 \text { and } \measuredangle 2 = x+40

(6x+50)  + (4x+40) = 180

6x+50 + 4x+40 = 180

10x+90 = 180

10x = 180 - 90

10x = 90

x = 9

Answer: x = 9
8 0
3 years ago
Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that
Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

\\ \mu = 85

\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

\\ z = -3

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

\\ P(z>-3) = 1 - P(z>3) = P(z

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

\\ P(z

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

5 0
3 years ago
John is a High School principal. He earns $62,299.92 a year and is paid on a semimonthly basis. How much is deducted per pay per
LenKa [72]

Answer alongwith Step-by-step explanation:

<u>1. Social Security</u>

Here Gross income = $62,300

Step 1 Find semiannual income

Semimonthly gross income = $62,300 / 24 = $2595.83

Step 2 Find the social security liability using social security rate and annual income

Social security rate is 6.2%

Social Security Liability = 6.2% x $2595.83 = $160.94 semimonthly payments

Step 3 Find the social security liability using social security rate and annual income

Deduction amount for Social security on monthly basis = $160.94 *2 =

$321.88 per month

<u>2. Medicare</u>

Here Gross income = $62,300

Step 1 Find semiannual income

Semiannual Gross income = $62,300 / 24 = $2595.83

Step 2 Find the social security liability using Medicare rate and annual income

Medicare rate is 1.45%

Medicare Liability = 1.45% x $2595.83 = $37.64 semimonthly payments

Step 3 Find the social security liability using Medicare rate and annual income

Deduction amount for Social security on monthly basis = $160.94 *2

= $75.28 per month

8 0
3 years ago
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