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joja [24]
2 years ago
7

Solve for x using the diagram of circle C. B В. (3x+49) (5x-7)

Mathematics
1 answer:
Nuetrik [128]2 years ago
4 0

Answer:

googl it

Step-by-step explanation:

its on googl and it has the anwser

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Help me with 2, 8, and 10 plz
OverLord2011 [107]

For #2:

<span> 3x^2 + 4 – 2x^2 + 6</span>

<span><span>You need to combine your like terms:
</span> 3x^2 – 2x^2= x^2</span>

4 + 6 = 10

This will now give you:

<span>X^2 +10</span>
3 0
3 years ago
The volume of a pyramid varies jointly with the base area of the pyramid and its height. The volume of one pyramid is 35 cubic i
Alla [95]
You first might want to divide 36 by 3, giving you 12. Multiply 12 by 5, which results in your answer of 60in^3. The equation for this is V = 1/3(blh)
6 0
3 years ago
A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro
pshichka [43]

Answer:

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed \frac{dx}{dt} = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}

(h)\frac{dh}{dt}=(x)\frac{dx}{dt}

(h)\frac{dh}{dt}=rx

\frac{dh}{dt}=\frac{rx}{h}

When automobile is 30 miles past the intersection,

For x = 30

\frac{dh}{dt}=\frac{30r}{h}

Since h=\sqrt{d^{2}+(30)^{2}}

Therefore,

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

3 0
3 years ago
It snowed from 9:43 PM to 11:37 PM. How long was it snowing?
dolphi86 [110]

Answer:

1 hour and 54 minutes and ignore this stuff sjsjsbdbsj

4 0
3 years ago
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Which expression is equivalent to 6m + (m – 2)(m + 7) + 3?
LuckyWell [14K]

Hello from MrBillDoesMath!

Answer:

m^2 + 11m - 11, which is the first choice


Discussion:

6m +  (m-2)(m+7) +3 =

6m  + (m^2 + 7m - 2m -14) + 3 =

(6m + 7m - 2m) + m^2 + (-14 + 3) =             combine similar terms

11m + m^2 -11 =

m^2 + 11m - 11


which is the first choice


Thank you,

MrB

4 0
3 years ago
Read 2 more answers
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