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shusha [124]
2 years ago
14

Please help, solve for x. Due today and all I’ve gotten are links :(

Mathematics
1 answer:
Nookie1986 [14]2 years ago
6 0

Answer:

I think it might be 0 im not to sure.

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7,-28,112,-448 what is the next 2 numbers
mote1985 [20]
 500 789       ........................................
3 0
3 years ago
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Trong has 12% of each paycheck automatically deposited to his savings account. His last paycheck was for $2,165. How much money
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18041.66 dollars to Trongs savings account
7 0
3 years ago
5) If Oskar bisects the diameter of a circle, what is he trying to construct?
pav-90 [236]

Answer:

Center = (5,-3) and radius = 7

Step-by-step explanation:

(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.

(6) The given equation is :

(x-5)^2+(y+3)^2=49

The general equation of circle is given by :

(x-a)^2+(y-b)^2=r^2 ...(1)

Where

(a,b) are the coordinates of the centre and r is the radius.

The given equation can be written as :

(x-5)^2+(y+3)^2=7^2 ..(2)

Comparing equation (1) and (2) we get :

a = 5, b = -3 and r = 7

So,

Center = (5,-3) and radius = 7

Hence, this is the required solution.

8 0
2 years ago
What is 12 divided by 1 using long division
sergeinik [125]

Answer:

12

Step-by-step explanation:

12 divided by 1 using long division is 12. As long as a number is divided by 1 the number is the same as the dividends number.

7 0
3 years ago
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Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?
Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between M(2, -3) and N(3, 1) will be,

MN = \sqrt{(3-2)^2+(1+3)^2}

      = \sqrt{1+16}

      = \sqrt{17}

Distance between M(2, -3) and O(-3, 1),

MO = \sqrt{(2+3)^2+(-3-1)^2}

      = \sqrt{25+16}

      = \sqrt{41}

Distance between N(3, 1) and O(-3, 1),

NO = \sqrt{(3+3)^2+(1-1)^2}

      = 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

(\sqrt{41})^2=(\sqrt{17})^2+6^2

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0
3 years ago
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