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nadezda [96]
3 years ago
15

Evaluate 11/12*12/121- -6/5*70/60

Mathematics
1 answer:
Oduvanchick [21]3 years ago
6 0

Answer:

82/55

Step-by-step explanation:

11/12 * 12/121 - -6/5 * 70/60 = 1/11 + 14/10 = 1/11 + 7/5 = 5/55 + 77/55 = 82/55

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The average of m, n, and -1 is 0. What is the value of m+n?
Oxana [17]

Answer: 1

==========================

Explanation:

To average a bunch of numbers, we add them up and divide by how many numbers there are. In this case, we'll divide by 3 since there are 3 numbers.

Add up the values: m+n+(-1) = m+n-1

Divide by 3: (m+n-1)/3

Set this equal to 0 since we're told the average is 0: (m+n-1)/3 = 0

Now let's isolate m+n. It might help to replace "m+n" with another variable, say P to get (P-1)/3 = 0.

Solve for P

(P-1)/3 = 0

P-1 = 3*0 .... multiply both sides by 3

P-1 = 0

P = 1 ... add 1 to both sides

m+n = 1 .... replace P with m+n

So that's why the answer is 1

5 0
3 years ago
I need help with this question plz
Vika [28.1K]
The answer is (4). all u have to do is see what makes sense.
5 0
3 years ago
Please help me with this. I thought the answer was 9 but I was wrong.
Lilit [14]

I think your answer is 28

3 0
3 years ago
Read 2 more answers
It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an
Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that n = 200, \pi = \frac{122}{200} = 0.61.

We want to build an 80% CI, so \alpha = 0.20, z is the value of Z that has a pvalue of 1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0
3 years ago
Selena has 31 days to complete her quilt for the county fair. The blue squares in the quilt can be sewn at a rate
Setler79 [48]

Answer:

The answer is a

Step-by-step explanation:

Becuase its right

6 0
3 years ago
Read 2 more answers
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