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Aleonysh [2.5K]
3 years ago
15

A bicycle has

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

Sales tax would be $53.

Just multiply the percentage by the listed price

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The area A (in square feet) of the rectangular shed is given by
a_sh-v [17]

This question is incomplete.

Complete Question

The area A (in square feet) of the rectangular shed is given by 6x³+7x²+11x+21.And one side of the rectangular is 2x+3. Use polynomial long division to find an expression for the length (in feet) of the shed.

Answer:

3x² - x +7

Step-by-step explanation:

Using the long division method:

We have :

Divisor : 6x³+7x²+11x+21

Dividend : 2x+3

Quotient : the length (in feet) of the shed = ???

Hence, we solve below

6x³+7x²+11x+21 ÷ 2x + 3

3x² -x + 7

______________________

2x+3 l 6x³+7x²+11x+21

6x³+9x²

__________

-2x²+11x

-2x²-3x

__________

14x+21

14x+21

_______

0

Therefore, an expression for the length (in feet) of the shed is 3x² - x +7

8 0
3 years ago
Solve for x. Show each step of the solution. 4.5(4 − x ) + 36 = 202 − 2.5(3x + 28)
bija089 [108]

Answlllllllllllllllllllllll

Step-by-step explanation:


5 0
3 years ago
How do I find the median for a congruent triangle
Andrej [43]
The length of a median is equal to half the square root of the difference of twice the sum of the squares of the two sides of the triangle that include the vertex the mediam is drawn from and the square of the side of the triangle the median is drawn to.

triangle sides by a, b, c.

ma=122c2+2b2−a2

mb=122c2+2a2−b2

mc=122a2+2b2−c2

3 0
3 years ago
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
The price of a sofa was reduced from $250 to $180. By what percentage was the price
Inessa [10]

Answer:

the price was reduced by 28%

7 0
3 years ago
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