<span>triangle ABD and the triangle CDB are similar
the options are </span><span>ASA and CPCTC</span>
Answer: The second image, the second image where b' is right above b is the correct answer for this, hope this helped!
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Step-by-step explanation:
We are given with a circle and we need to find the <em>equation of the circle</em> , but first let's recall that , the equation of a circle with radius<em> 'r'</em> and centre at <em>(h,k) </em>is given by
Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here <em>(h,k) = (0,0)</em> .Which means that the centre is located at the point whose coordinates are<em> (0,0)</em> which is also known as origin . Now , finding the equation of the circle :-


<em>This is the required equation of Circle</em>