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Aleonysh [2.5K]
3 years ago
5

Plz help! Answer at least one of these questions and i will give you brainly! It’s ok if you don’t know them all!

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
8 0
For number 3 it is 56 pints! i’ll do the other ones in a second
diamong [38]3 years ago
7 0
3: 7gallons = 56 pints
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A letter is selected from the words in accommodation list all the possible outcomes
Luda [366]
Since a letter is selected from      a c c o m m o d a t i o n

Possible outcome:

It could be any of the thirteen letters. There are thirteen possibilities.

a      c     c     o       m     m     o     d     a    t      i     o     n          
8 0
3 years ago
I dont understand the problem
Roman55 [17]

Answer:

equation of a line:

y = mx+c

1) find the gradient, m

m =  \frac{y2 - y1}{x2 - x1}

m =  \frac{ - 4 - ( - 4)}{ - 10 - 1}

m = 0

2) find y-intercept, c using coordinate (1,-4)

y = mx + c

-4 = 0(1) + c

c = -4

the equation of line:

y = mx+c

y = 0(x) + c

y = c

y = -4

6 0
3 years ago
If you could please help that could be great TYSM
kobusy [5.1K]

Answer:-98.4+18.8

Step-by-step explanation:

7 0
3 years ago
PLEASEEE HELP On a coordinate plane, the vertices of triangle ABC are A(−3, 1), B(6, 4), C(2, 5). The vertices are translated 4
shutvik [7]

Answer:

A (1,-2) B(10,1) C(6,2)

Step-by-step explanation:

You add 4 to the x value and subtract 3 from the y value to get the answer.

7 0
3 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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