Answer:
Equation shown
Step-by-step explanation:
Eq(1): x-3y=-12
X=-12+3y
=-4+y
Eq(2): x-3y=-6
X=-6+3y
=-2+y
Answer:
x = 5m/s
Step-by-step explanation:
Distance flying out = 12 km (headwind)
Distance flying back = 12 km (tailwind)
total distance = 12 + 12 =24 km
wind speed = 1km/h
speed going out (with headwind) = (x - 1) km/h
speed coming back (with tailwind) = (x + 1) km/h
Time taken to go out = distance going out / speed going out
= 12 / (x-1)
Time taken to come back = distance coming back / speed coming back
= 12 / (x+1)
total time = time taken to go out + time taken to come back
5 =[ 12/(x-1) ] + [ 12/(x-1)]
expanding this, we will get
5x² - 24x - 5 = 0
solving quadratic equation, we will get
x = -1/5 (impossible because speed cannot be negative)
or
x = 5 (answer)
The answer is Answer 30 i think
Answer:
C, -50*hours+475
Step-by-step explanation:
We are trying to get the total distance left, so we are subtracting the distance traveled from the total. If we travel at 50 miles per hour then the distance traveled is equal to 50*hours and if you subtract that from the total you ahve the distance left.
