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Ivahew [28]
2 years ago
15

Someone, please help me on this one

Mathematics
2 answers:
S_A_V [24]2 years ago
4 0

Answer:

D. (f + g )( x ) = 6x³ - 3x² + 7x - 8

Step-by-step explanation:

<u>Given :-</u>

  • f ( x ) = 4x² + 7x - 3.
  • g ( x ) = 6x³ - 7x² - 5.

<u>To Find :-</u>

  • ( f + g ) ( x ).

<u>Solution :-</u>

(f + g )( x ) = 4x² + 7x - 3 + 6x³ - 7x² - 5.

Arranging like terms.

(f + g )( x ) = 6x³ - 7x² + 4x² + 7x -5 - 3

Combine like terms.

(f + g )( x ) = 6x³ - 3x² + 7x - 8

creativ13 [48]2 years ago
3 0

Answer:

D

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= 4x² + 7x - 3 + 6x³ - 7x² - 5 ← collect like terms

= 6x³ - 3x² + 7x - 8

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Citrus2011 [14]

Answer:

17.9:13

Step-by-step explanation:

I know this because in order to find the percentage of 310, you must mutiply 310 by the percentage.

The number of students who like basketball:

310 x 0.05774 = 17.9

The number of students who don't like basketball:

310 x 0.04726 = 13

Hope this helps! :)

4 0
2 years ago
Read 2 more answers
What is the answer to 4x + 27
Alla [95]

Answer:

Step-by-step explanation:

4x+27

----  ----

4       4

x=6.75 or x=7

7 0
3 years ago
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Hunter-Best [27]

Answer: 11

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Hope that had helped

4 0
2 years ago
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Plsss help me :((((((
Valentin [98]

Answer:

Y-intercept: 0

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7 0
3 years ago
The wildflowers at a national park have been decreasing in numbers. There were 300 wildflowers in the first year that the park s
Scorpion4ik [409]
Although the number of new wildflowers is decreasing, the total number of flowers is increasing every year (assuming flowers aren't dying or otherwise being removed). Every year, 25% of the number of new flowers from the previous year are added.
The sigma notation would be:
∑ (from n=1 to ∞) 4800 * (1/4)ⁿ , where n is the year. 
Remember that this notation should give us the sum of all new flowers from year 1 to infinite, and the values of new flowers for each year should match those given in the table for years 1, 2, and 3
This means the total number of flowers equals:
Year 1: 4800 * 1/4 = 1200 ]
+
Year 2: 4800 * (1/4)² = 300
+ 
Year 3: 4800 * (1/4)³ = 75
+  
Year 4: 4800 * (1/4)⁴ = 18.75 = ~19 (we can't have a part of a flower)
+
Year 5: 4800 * (1/4)⁵ = 4.68 = ~ 5
+ 
Year 6: 4800 * (1/4)⁶ = 1.17 = ~1
And so on. As you can see, it in the years that follow the number of flowers added approaches zero. Thus, we can approximate the infinite sum of new flowers using just Years 1-6:
1200 + 300 + 75 + 19 + 5 + 1 = 1,600

8 0
3 years ago
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