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Brums [2.3K]
3 years ago
13

Plsss help me :((((((

Mathematics
1 answer:
Valentin [98]3 years ago
7 0

Answer:

Y-intercept: 0

Equation: y = 5/4x

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If x=9 and y=−3, evaluate the following expression:4/x−yGive your answer as a fraction in its simplest form.​
qwelly [4]
Answer:1/3
4/9-(-3)=4/12=
1/3
6 0
3 years ago
Read 2 more answers
Two trains leave stations 360 miles apart at the same time and travel toward each other. One train travels at 70 miles per hour
cricket20 [7]
S=d/t     ⇒d=s*t
s=speed
d=distance
t=time

The first train :
d=x

x=70 miles/h*t                             ⇒   x=70t  (1)

The second train
d=360 miles - x

360 miles - x=80 miles/h*t          ⇒360-x=80t   ⇒ x=360-80t   (2)

therefore, with the equations (1) and (2) we have a systeme of equations:

x=70t
x=360-80t

we can solve this system of equations by equalization method.

70t=360-80t
70t+80t=360
150t=360
t=360/150=2.4     (≈2 hour  24 minutes)

Answer:  the first train meet with the second train in 2 hour 24 minutes. 


3 0
3 years ago
Read 2 more answers
A 3 cm x 3 cm rectangle sits inside a circle with radius of 4 cm.
Vitek1552 [10]

Given:

Rectangle inside a circle.

To find:

The area of the shaded region.

Solution:

Length of a rectangle = 3 cm

Width of a rectangle = 3 cm

Area of a rectangle = length × width

                                    = 3 × 3

Area of a rectangle = 9 cm²

Radius of a circle = 4 cm

Area of a circle = πr²

                             = 3.15 × 4²

Area of a circle = 50.24 cm²

Area of shaded region = Area of circle - Area of rectangle

                                      = 50.24 - 9

                                      = 41.24 cm²

The area of the shaded region is 41.24 cm².

5 0
3 years ago
Read 2 more answers
Whats the relationship between the 6s in 660,472?
Bond [772]
The six in the right is 10times more than the 6 on the left then the other way arounft
6 0
3 years ago
Read 2 more answers
A high school track coach has just purchased a new stopwatch. The stopwatch manual states that the stopwatch has an uncertainty
grigory [225]

Answer:

The new stopwatch will not be that useful in timing the sprint team at the school's last track meet.

Step-by-step explanation:

Given:

Accuracy of the stopwatch = ± 0.05 s

The time of the first place sprinter = 12.04 s

The time of the second-place sprinter = 12.07 seconds

Now,

If sprinters were timed with the new stopwatch,

thus,

First sprinter's time would have been between

=  12.04 - 0.05  and 12.04 + 0.05

= 11.99 and 12.09

or

between the interval [11.99 , 12.09]

while

Second sprinter's time would have been between

= 12.07 - 0.05 =and 12.07 + 0.05

= 12.02  and 12.12

or

between the interval [12.0.2 , 12.12]

Hence,

There is an overlap between the worst time of the first sprinter  i.e 11.99 and the best time of the second sprinter i.e 12.02

Hence,

The new stopwatch will not be that useful in timing the sprint team at the school's last track meet.

7 0
3 years ago
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