Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
Answer:
The advantage for the above condition is as follows:-
Explanation:
- If a user creates a defined constant variable and assigns a value on its and then uses that variable instead of the value, then it will a great advantage.
- It is because when there is a needs to change the value of that variable, then it can be done when the user changes the value in one place. There is no needs to change the vale in multiple places.
- But if there is a value in multiple places instead of a variable and there is no constant variable, then the user needs to change the value in multiple places.
For the list of application, either check in the book or come up with yourself.
All application not depend on the 32 bit or 64 bit processor.
Answer:
The correct approach is "Phased".
Explanation:
- The pilot step requires just to validate the development's implementation goals and objectives and then when the SDMX objects were introduced to development, several perhaps all problems have indeed been detected as well as logged through so that they're being corrected either by the detailed technical advisory committee.
- The staggered or phased approach towards deployment provides the time possible to obtain the very next knowledge on evaluation criteria, staff including diverse cultures such that the strategy produced could be customized accordingly.
Answer:
<u>algorithm</u>
original = float(raw_input("Enter initial balance: "))
interest = float(raw_input("Enter promised return: "))
expenses = float(raw_input("Enter monthly expenses: "))
interest = interest / 100 / 12
month = 0
balance = original
if balance * interest - expenses >= 0:
print "You don't need to worry."
else:
while balance + balance * interest - expenses >= 0: # negation of the if condition
balance = balance + interest * balance # in one month
balance = balance - expenses
month = month + 1
print month, balance
print month / 12, "years and", month % 12, "months"
