Answer:
a
Step-by-step explanation:
For y=ax²+bx+c
if a>0 then it opens up
if a<0 then it opens down
hmm, y intercept is where x=0
x intercept is where y=0
so
f(x)=3x²+4x+16
3>0 so opens up
y intercep
x=0
3(0)²+4(0)+16
16
y intercept is y=16
x intercept
0=f(x)=3x²+4x+16
there are no real solutions since the discriminant is negative
no x intercepts or no zeroes
so
opens up
y intercept of 16
no zeroes
Answer:
=4x2+12x+9
Step-by-step explanation:
(2x+3)(2x+3)
(happy to help)
◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
For this case we have the following polynomial:
x2 - 11x + 24
We note that the polynomial can be rewritten as:
(x-3) (x-8)
Answer:
A common factor binomial for this case is given by:
(x-3)
option B
