Your answer should be B!
I hope this helped!
3+ (2) 4+ 1 = 12
Good luck
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
4.5 : i think thats the answer i don't know
Total money spent is $11425 buying 75 animals
each chicken costs $65 so 50 costed the farmer $3250
each cow costs $45 so 15 cows costed the farmer $675
ducks purchased were 10
to find how much the ducks costs we will add the money spent the farmer and subtract it from the total amount spent.
11425-3250-675=$7500
10 ducks = $7500
so one duck costs 7500/10=$750
the price for each duck is $750