Answer:
3y-+1
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Firstly we find the x value. x-7=0; x=7
Secondly we introduce x value in 1st ecuation. So
(7-3)^2 +(y+1)^2=16, 16+y^2+2y+1=16,
Consider this ecuation: y^2+2y+1=0
y1=( -b+Δ)/ 2a, y2= (-b-√Δ)/2a, Δ=√b^2-4ac=√4-4=0
y1,2= -2/2= -1
1 Real solution x=7 and y= -1.
Answer:
37
Step-by-step explanation:
<BRD & <FRK are vertical angles
Answer:
19.27
Step-by-step explanation:
<u>To </u><u>find</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Answer</u><u> </u><u>:</u><u>-</u><u> </u>
As we know that ,
→ cos ∅ = b/h
→ cos 33° = 16/x
→ 0.83 = 16/x
→ x = 16/0.83
→ x = 19.27
Answer:
(-3, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -x + 1
2x + 3y = 6
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x + 3(-x + 1) = 6
- Distribute 3: 2x - 3x + 3 = 6
- Combine like terms: -x + 3 = 6
- Isolate <em>x</em> terms: -x = 3
- Isolate <em>x</em>: x = -3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -x + 1
- Substitute in <em>x</em>: y = -(-3) + 1
- Simplify: y = 3 + 1
- Add: y = 4