3 years ago

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Mathematics

1 answer:

jekas [21]3 years ago

6 0

Answer:

wait ill work this out for you

Step-by-step explanation:

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Write a x (-a)x 13 x a x (-a) x 13 in power notation

miss Akunina [59]

Answer:

$a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Step-by-step explanation:

The given expression

$a\times (-a)\times 13\times a\times (-a)\times 13$

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

$a\times (-a)\times 13\times a\times (-a)\times 13$

= $[13\times13][(a\times (-a)\times a\times (-a)]$

$13\times13 = 13^{2}$ , $a\times a = a^{2}$ , $(-a)\times (-a) = (-a)^{2}$

So,

$=[13^{2}][a^2\times (-a)^2]$

$(-a)^2 = a^{2}$

So,

$=[13^{2}][a^2\times a^2]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=[13^{2}][a^{2+2}]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=13^{2}\times a^{4}$

$=a^{4}\times 13^{2}$

Therefore, $a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Keywords: power notation

Learn more about power notation from brainly.com/question/2147364

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5 0

3 years ago

In the year 2005, a total of 750 fish were introduced into a manmade lake. The fish population was expected to grow at a rate of

rewona [7]

Exponential change can be modeled by:
N = N(0) x λⁿ; where λ is the rate of change. It is greater than 1 when there is growth and less than 1 when there is decay. n is the number of time periods passed.
λ is 1 + 0.083 = 1.083
N(0) is the initial value of 750
n is 2050 - 2005 = 45 years
N = 750 x (1.083)⁴⁵
= 27,000 fish

6 0

3 years ago

Read 2 more answers

Solve the exponential equation. Write the exact answer with natural logarithms and then approximate the result correct to three

tester [92]

Answer:

Fraction form: x = ln(5)/ln(10)

Decimal form: 0.69897000

please mark brainliest

3 0

3 years ago

What is the best answer to solution of x^2 + 16 = 0?