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horsena [70]
3 years ago
11

On a soccer team, 40% of the goals are

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

40 \div 100 \times 70 \\ 4 \times 7 = 28 \\ 70 - 28 = 42

Step-by-step explanation:

First find 40% of 70, which is 28

Then subtract the 28 from 70 to find the goals scored by the rest of the team

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Help please !!!!?!!!!
Bingel [31]

Answer:

m < 2 = 45°

Step-by-step explanation:

m < 1 and m < 3 are corresponding angles that lie on the same side of the transversal.  Since they are corresponding angles, then it means that they have the same measure.

Therefore, if m < 1 = 135°, then m < 3 = 135°.

Also, the sum of m < 2 and m < 3 = 180° because they are supplementary angles.

Therefore:

m < 2 + m < 3 = 180°

m < 2 + m < 135° = 180°

m < 2 = 180° - m < 135°

m < 2 = 45°

4 0
2 years ago
Im solving variables i need to simplify -5x + 3 (x+5) = -3
victus00 [196]

Answer:

x=9

Step-by-step explanation:

Add similar elements: -5x+3x=-2x

-2x+15=-3

Subtract 15 from both sides

-2x + 15-15=-3-15

Simplify

-2x=-18

Divide both sides by -2

-21/-2 = -18/-2

Simplify

x=9

8 0
3 years ago
Read 2 more answers
Who can solve this in 1 min 5678÷78
andreev551 [17]

It is 72.7948718

~Hope that helped!~

~Izzy <3

5 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
What is m ZDFC?<br><br> O45°<br> O 80°<br> O 125°<br> O 135
Law Incorporation [45]
I believe it’s 80 hope it helps
4 0
3 years ago
Read 2 more answers
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