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german
2 years ago
9

A school is electing students for class officers. There are four offices: president, vice president, secretary, and treasurer. T

he student with the most votes becomes president, second highest number of votes is vice president, and so on. If there are students in this class, how many ways can students be elected?
Mathematics
2 answers:
Natasha2012 [34]2 years ago
6 0

Answer:

84,264

Step-by-step explanation:

Neko [114]2 years ago
4 0

Answer:

84,264

Step-by-step explanation:

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A regular pentagon ABCDE is shown work out angle x
kow [346]

Answer:

108 degrees inside each corner

Step-by-step explanation:

360/5=72

180-72=108

5 0
3 years ago
a rally car course covers 51 5.97 miles .the winning car completed the course in 6.5 hours. what was the average speed of the wi
Artyom0805 [142]
Assuming the speed is in miles per hour, simply divide the total distance by time.
515.97/6.5
The answer is 79.38 miles per hour
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3 years ago
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif
algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0
2 years ago
Andrew can jog 144 miles in 11 hours. Enter the number of miles he can jog in 1 hour.​
katrin2010 [14]
144/11= 13.09

Andrew can jog 13.09 miles in one hour.
8 0
3 years ago
What are the roots of the equation?
Mariana [72]

Answer:

3x2

Step-by-step explanation:

because it is

4 0
3 years ago
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