13x+6-4x+8= Simplify the following expression.
2 answers:
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The first term in a sequence is sometimes referred to as as opposed to
because
represents the initial value
The question refers to the difference between the terms
and
The terms in a sequence are represented by a subscript number.
Take for instance a₂ or T₂ represents the second term.
However, when the first term is represented by a₀ instead of a₁.
It means that the sequence has an initial value, other than the first term.
Even though the words "first" and "initial" are synonyms, they do not entirely represent the same thing.
Take for instance, a₀ can be used instead of a₁ in the following scenario
<em>The population of a country is 1000 in 1996 and The country experiences an increment of 250 people every year after 1996.</em>
<em />
The above means that:
a₀ = 1000 --- the initial year
a₁ = 1000 + 250 = 1250 ---- the first year after 1996 (i.e. 1997)
Read more about sequence at:
#SPJ1
AD is the diagonal of a 6 by 15 rectangle,
31.
Choice A
32.
Choice A
33.
7 - 4x = 7y
4x + 7y = -7
The parallel through (2,0) keeps the coefficients on x and y and just changes the constant:
4x + 7y = 4(2)+7(0)= 8
7y = -4x + 8
y = (-4/7) x + 8/7
Choice B
Answer:
a. V = 4/3
b. See attachment
Step-by-step explanation:
a.
Given
Z = x² + y²
V = ∫ ∫ (x² + y²) dxdy {0,1}{0,y} + ∫ ∫ (x² + y²) dxdy {0,1}{x,2-x}
V = ∫ ∫ (x² + y²) dxdy {0,1}{x,2-x}
Integrate with respect to y
V = ∫ x²y+ y³/3 dx {0,1}{x,2-x}
V = ∫ x²(2-x) + (2-x)³/3 - x²(2) - (2)³/3 dx {0,1}
V = ∫ 2x² -7x³/3 + (2-x)³/3 dx {0,1}
V = 2x³/3 - 7x⁴/12 + (2-x)⁴/12 {0,1}
V = (⅔ - 7/4 + 2/12) - (0-0+16/12)
V = 4/3
