1 answer:
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We know that .
And .
Hope this helps.
Answer
(a)
(b)
Step-by-step explanation:
(a) δ(t)
where δ(t) = unit impulse function
The Laplace transform of function f(t) is given as:
where a = ∞
=>
where d(t) = δ(t)
=>
Integrating, we have:
=>
Inputting the boundary conditions t = a = ∞, t = 0:
(b)
The Laplace transform of function f(t) is given as:
Integrating, we have:
Inputting the boundary condition, t = a = ∞, t = 0:
Answer:
The width of the frame is 0.0746 meters
Step-by-step explanation:
We are told that after the frame has been attached to the solar collector, the area that is left exposed is . As we see in the figure, the dimensions of this area are
and
where is the width of the frame.
The product of these dimensions must equal the exposed area:
Now since and
we have:
we expand this and solve for x using the quadratic formula:
we get two solutions:
We take the second solution i.e , because first one gives a width larger than the dimensions of the solar collector which cannot be possible.
Thus the width of the frame is 0.0746 meters.
