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3 years ago

Divide 15 by v. Then, subtract 7.

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

6 0

Answer:

A 15/V-7

Step-by-step explanation:

rosijanka [135]3 years ago

4 0

A is the correct answer

hope that helps:)

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What is the difference between slope on a table and slope on a graph

Stolb23 [73]

On a table there is no way you could calcualte rise over run, but other than that they are veryyyyyy similar

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3 years ago

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the center of a circle is on the line y=2x and the line x=1 is tangent to the circle at (1,6).find the center and the radius

Julli [10]

The radius and the center of the circle are 4 units and (1,2), respectively

<h3>How to determine the center and the radius?</h3>

The center of the circle is on

y = 2x and x = 1

Substitute x = 1 in y = 2x

y = 2 * 1

Evaluate

y = 2

This means that the center is

Center = (1, 2)

Also, we have the point of tangency to be:

(x, y) = (1, 6)

This point and the center have the same x-coordinate.

So, the distance between this point and the center is

d = 6 - 2

d = 4

This represents the radius

Hence, the radius and the center of the circle are 4 units and (1,2), respectively

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brainly.com/question/10618691

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2 years ago

Kai calculates that he spends 15% of a school day in science class. If he spends 75 minutes in science class, how many minutes d

kupik [55]

$x-minutes\ in\ school\\15\%=0.15\\100\%=1\\\\From\ proportion:\\\\75\ \ \ -\ \ \ 0.15\\x\ \ \ \ \ -\ \ \ 1\\\\0.15x=75\ \ \ |:0.15\\x=500\\\\He\ spends\ 500\ minutes\ in\ school.$

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4 years ago

Read 2 more answers

. The time required for a technician to machine a specific component is normally distributed with a mean of 2 hours and a standa

erma4kov [3.2K]

Answer:

a) There is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

b) There is a 0.42% probability that the technician will require at least 2.75 hours to complete one component

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have to be careful. The mean is in hours, while the standard deviation is in minutes. I am going to work with both in hours, as the problem states. 17 minutes is 0.283 hours, so:

$\mu = 2, \sigma = 0.283$

(a.) What is the probability that the technician can machine one component in 1.5 hours or less?

This probability is the pvalue of the Zscore when $X = 1.5$ . So:

$Z = \frac{1.5 - 2}{0.283}$

$Z = \frac{-0.5}{0.283}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

(b.) What is the probability that the technician will require at least 2.75 hours to complete one component?

The pvalue of the score of $X = 2.75$ is the probability that the technican will require less than 2.75 hours to complete one component. The probability that he will require at least 2.75 hours to complete one component is 1 subtracted by this pvalue. So: