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3 years ago

What’s the volume of the figure?

Mathematics

1 answer:

Svet_ta [14]3 years ago

7 0

Answer:

4,050 ft^3

Step-by-step explanation:

Separate the figure into a cube and a square pyramid.

Volume of the cube (a^3):

15 x 15 x 15 = 3,375

3,375 ft^3

Volume of the square pyramid (lwh/3):

15 x 15 x 9/3 = 675

675 ft^3

Add the volumes of both figures:

675 ft^3 + 3,375 ft^3 = 4,050

The volume of the whole figure is 4,050 cubic feet.

Hope this helps!

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Megan is trying to find the length of the segment using the Pythagorean Theorem

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3 years ago

Explain how to check multiplication using addition and division ñ. Include an example in your explanation.

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3 years ago

In the diagram the length of segment TR can be represented by 5x-4.

masya89 [10]

Answer: The correct option is D, i.e., 15 units.

Explanation:

It is given that the length of segment TR can be represented by 5x-4.

From figure it is noticed that the side TR and RV is equal and the length of segment RV is 2x+5. So,

$5x-4=2x+5$

$3x=9$

$x=3$

The value of x is 3, so the length of side RV is,

$2x+5=2(3)+5=11$

In triangle TRS and angle VRS,

TR=VR

$\angle TRS=\angle VRS=90^{\circ}$

RS=RS (common side)

By SAS rule of congruence triangle,

$\triangle TRS\cong\triangle VRS$

Therefore the side TS and VS are congruent sides.

From figure it is noticed that the length of side TS is 6x-3, therefore the length of side VS is also 6x-3.

$VS=6x-3=6(3)-3=15$

Hence, the length of side VS is 15 units and option D is correct.

4 0

4 years ago

Read 2 more answers

Q2.What is the ratio of volumes of the two cylinders formed by rolling a sheet of dimensions lxb in two different ways? Q3.What

Kobotan [32]

Answer:

2. b : l

3. 20cm

4. 49 $cm^{2}$

5. $(2\pi+1):2\pi$

Step-by-step explanation:

<u>Solution 2:</u>

Let cylinder is rolled along 'l':

Height of cylinder , h = length of rectangle = l

Perimeter of base = b

Let 'r' be the radius of cylinder's base:

$2\pi r = b\\\Rightarrow r = \dfrac{b}{2\pi}$

Volume of a cylinder is given as:

$V = \pi r^{2} h$

Putting the values:

$V_1 = \pi (\dfrac{b}{2\pi})^2 l\\\Rightarrow V_1 = (\dfrac{b^2}{4\pi}) l$

Let cylinder is rolled along 'b':

Height of cylinder , h = length of rectangle = b

Perimeter of base = l

Let 'r' be the radius of cylinder's base:

$2\pi r = l\\\Rightarrow r = \dfrac{l}{2\pi}$

Volume of a cylinder is given as:

$V = \pi r^{2} h$

Putting the values:

$V_2 = \pi (\dfrac{l}{2\pi})^2 b\\\Rightarrow V_2 = (\dfrac{l^2}{4\pi}) b$

Taking ratio:

$V_1:V_2 = \dfrac{(\dfrac{b^2}{4\pi}) l}{(\dfrac{l^2}{4\pi}) b} = b:l$

Solution 3:

Rectangle is rolled along its length to make a cylinder, so height will be equal to its length.

$\therefore$ height of cylinder = 20 cm

Solution 4:

Side of square = 7 cm

Height of cylinder =Side of square = 7 cm

7 cm will be the circumference of the circle.

i.e. $2\pi r$ = 7 cm

Curved surface area of a cylinder:

$CSA = 2\pi rh$

Putting the above values:

CSA = 7 $\times$ 7 = 49 $cm^{2}$

Solution 5:

As calculated in above step:

CSA = $2\pi rh =$ 7 $\times$ 7 = 49 $cm^{2}$

Total surface area = $2\pi r^{2} + 2\pi r h$

Calculating value of r:

$2\pi r$ = 7 cm

$\Rightarrow 2 \pi r = 7\\\Rightarrow r = \dfrac{7}{2\pi}$

Total surface area =

$2\pi (\dfrac{7}{2\pi})^{2} + 49\\\Rightarrow \dfrac{49}{2\pi}+49\\\Rightarrow 49(\dfrac{1}{2\pi}+1) cm^2$

Ratio of TSA: CSA is

$49(\dfrac{1}{2\pi}+1) cm^2 : 49 cm^2\\\Rightarrow (\dfrac{1}{2\pi}+1):1\\\Rightarrow (2\pi+1): 2\pi$

5 0

3 years ago