What is the simplified expression for

If you travel at a rate of 45 miles per hour, how many minutes will it take you to travel 1 mile

gavmur [86]

1 minute and 15 seconds.

8 0

3 years ago

I will give Brainliest!!

sergey [27]

The value of y in the triangle is 6°.

<h3>How to calculate the value of y in the triangle?</h3>

Firstly, it's important to note that a triangle has the total angles of 180°.

Based on the information, the triangle has interior angle measures of 11y, 10y + 10°, and 10y - 16º.

The value of y in the triangle will be illustrated thus:

11y + 10y + 10 + 10y - 16 = 180

31y - 6 = 180

31y = 180 + 6.

31y = 186

Divide.

y = 186 / 31

y = 6

The value of y is 6.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ1

5 0

1 year ago

The graph shown here is the graph of which of the following rational functions

JulsSmile [24]

Answer:

The answer is 100% B

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

18.Lupe and her friends spent $20 on snack mix and water. They bought x bags of snack mix and y bottles of water. They bought a

Readme [11.4K]

Answer:

bags of snack = x = 6

bottles of water = y = 5

Step-by-step explanation:

The system of equations can be used to determine how many of each item they bought.

20.00=2.50x+1.00y

11=x+y

how many bags of snack mix did they buy?

Let

bags of snack = x

bottles of water = y

20.00 = 2.50x + 1.00y (1)

11 = x + y (2)

From (2)

x = 11 - y

Substitute x = 11 - y into (1)

20.00 = 2.50x + 1.00y

20.00 = 2.50(11 - y) + 1.00y

20.00 = 27.5 - 2.50y + 1.00y

20.00 - 27.5 = -2.50y + 1.00y

-7.5 = -1.5y

y = -7.5/-1.5

y = 5

Substitute y = 5 into (2)

11 = x + y

11 = x + 5

11 - 5 = x

x = 6

bags of snack = x = 6

bottles of water = y = 5

7 0

3 years ago

Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

3 years ago