Question

Hi,there,can you solve this equation. 4x*sqrt(2x-x²)=2x-1

Answer 1

Answer:

Step-by-step explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 =  4x^2 -4x + 1

$-16x^4+32x^3-4x^2+4x-1=0$

$x = 1.92887$