3 years ago

Hi,there,can you solve this equation. 4x*sqrt(2x-x²)=2x-1

Mathematics

1 answer:

horrorfan [7]3 years ago

8 0

Answer:

Step-by-step explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 = 4x^2 -4x + 1

$-16x^4+32x^3-4x^2+4x-1=0\\$

$x = 1.92887$

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