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Dmitry_Shevchenko [17]
3 years ago
5

Hi,there,can you solve this equation. 4x*sqrt(2x-x²)=2x-1

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

Step-by-step explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 =  4x^2 -4x + 1

-16x^4+32x^3-4x^2+4x-1=0\\

x  = 1.92887

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Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

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To learn more on piecewise functions: brainly.com/question/12561612

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