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sergejj [24]
3 years ago
14

What is the LEAST possible integer value and the greatest

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Answer:

hey mate I guess ur question is incomplete......after greatest what is it? plz check

Oksi-84 [34.3K]3 years ago
7 0

Answer:

Step-by-step explanation:

-4 < x < 9

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Consider the figure shown below. Find the value of BL
Gnesinka [82]

Answer:

BL = 2

Step-by-step explanation:

Given:

AL = 3

AC = 10

BC = 9

AL = AM = 3 (tangents drawn form am external point)

CM = AC - AM

CM = 10 - 3

CM = 7

CM = CN = 7 (tangents drawn form am external point)

BN = BC - CN

BN = 9 - 7

BN = 2

BN = BL = 2 (tangents drawn form am external point).

BL = 2

7 0
3 years ago
Are these triangles similar?
sattari [20]

Answer:

yes they are similar

Step-by-step explanation:

6 0
3 years ago
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8) BRAINLIEST AND 15 POINTS! PLS HELP ASAP
algol13

Answer:

a.) Between 0.5 and 3 seconds.

Step-by-step explanation:

So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.

If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.

Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.

So, the answer is a.) between 0.5 and 3 seconds.

4 0
3 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> (5 + 6i)(5 - 6i)
lubasha [3.4K]

\boxed{\underline{\bf \: ANSWER}}

\sf \: ( 5 + 6 i ) ( 5 - 6 i )

Multiply complex numbers 5+6i and 5-6i in the same way as you multiply binomials.

\dashrightarrow \sf 5\times 5+5\times \left(-6i\right)+6i\times 5+6\left(-6\right)i^{2}

By definition, i² is -1.

\dashrightarrow \sf 5\times 5+5\times \left(-6i\right)+6i\times 5+6\left(-6\right)\left(-1\right)

Do the multiplications.

\dashrightarrow \sf \: 25-30i+30i+36

Now cancel -30i & +30i

\dashrightarrow \sf \: 25 \:  \bcancel{- 30i}  \:  +  \: \bcancel{30i}+36

Now the equation becomes

\dashrightarrow \sf \: 25 \:  + 36 \\ \dashrightarrow  \boxed{\bf \: 61}

________

Hope it helps.

ŕάίήвόώşάĻţ2²2²

5 0
3 years ago
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Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
insens350 [35]
1) We have that there are in total 6 outcomes If we name the chips by 1a, 1b, 3 ,5 the combinations are: 1a,3 \ 1b, 3 \1a, 5\ 1b, 5\ 3,5\1a,1b. Of those outcomes, only one give Miguel a profit, 1-1. THen he gets 2 dollars and in the other cases he lose 1 dollar. Thus, there is a 1/6 probability that he gets 2$ and a 5/6 probability that he loses 1$.
2) We can calculate the expected value of the game with the following: E=\frac{1}{6}*2- \frac{5}{6} *1. In general, the formula is E= \sum{p*V} where E is the expected value, p the probability of each event and V the value of each event. This gives a result of E=2/6-5/6=3/6=0.5$ Hence, Miguel loses half a dollar ever y time he plays.
3) We can adjust the value v of the winning event and since we want to have a fair game, the expecation at the end must be 0 (he must neither win or lose on average). Thus, we need to solve the equation for v:
0=\frac{1}{6}v -\frac{5}{6} =0. Multiplying by 6 both parts, we get v-5=0 or that v=5$. Hence, we must give 5$ if 1-1 happens, not 2.
4) So, we have that the probability that you get a red or purple or yellow sector is 2/7. We have that the probability for the blue sector is only 1/7 since there are 7 vectors and only one is blue. Similarly, the 2nd row of the table needs to be filled with the product of probability and expectations. Hence, for the red sector we have 2/7*(-1)=-2/7, for the yellow sector we have 2/7*1=2/7, for the purple sector it is 2/7*0=0, for the blue sector 1/7*3=3/7. The average payoff is given by adding all these, hence it is 3/7.
5) We can approach the problem just like above and set up an equation the value of one sector as an unknown. But here, we can be smarter and notice that the average outcome is equal to the average outcome of the blue sector.  Hence, we can get a fair game if we make the value of the blue sector 0. If this is the case, the sum of the other sectors is 0 too (-2/7+0+2/7) and the expected value is also zero.
6) We want to maximize the points that he is getting. If he shoots three points, he will get 3 points with a probability of 0.30. Hence the average payoff is 0.30*3=0.90. If he passes to his teammate, he will shoot for 2 points, with a success rate of 0.48. Hence, the average payoff is 0.48*2=0.96. We see that he should pass to his player since 0.06 more points are scored on average.
7) Let us use the expections formula we mentioned in 1. Substituting the possibilities and the values for all 4 events (each event is the different profit of the business at the end of the year).
E=0.2*(-10000)+0.4*0+0.3*5000+0.1*8000=-2000+0+1500+800=300$
This is the average payoff of the firm per year.
8) The firm goes even when the total profits equal the investment. Suppose we have that the firm has x years in business. Then x*300=1200 must be satisfied, since the investment is 1200$ and the payoff per year is 300$. We get that x=4. Hence, Claire will get her investment back in 4 years.
8 0
3 years ago
Read 2 more answers
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