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katrin2010 [14]
3 years ago
8

Integers53 + (-26 )​

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0
<h2>✨ Question ✨</h2>

53 + (-26 )

<h2>✨ Answer ✨</h2>

\:  \:  \:  \:  \: \:  \:  \:  \:   \purple{ \boxed{ \boxed{ \huge{ \tt{ \: 37 \: }}}}}

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Let a, b be nonzero numbers. What is the following number? (a/b)^9/(a/b)^2
elena-s [515]

Answer:

it will just. e (a/b)^7

Step-by-step explanation:

since its divide, according to the rule of indices, it will just be to the power of 9-2 =7

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3 years ago
How much more does she need to reach her goal
sashaice [31]
She need to reach her goal is adding 175+120=295 I think.
4 0
3 years ago
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Simplify: (7a − 9c) − (−12a − 33c) − (−21a + 10c)
CaHeK987 [17]
Distribute all the negatives: 7a-9c+12a+33c+21a-10c

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4 years ago
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A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 85% conf
Sladkaya [172]

Answer:

The 85% confidence interval for the mean is between 5.5 and 5.7 fast food meals consumed per week.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.075 = 0.925, so z = 1.44

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.44*\frac{1.3}{\sqrt{548}} = 0.08

The lower end of the interval is the sample mean subtracted by M. So it is 5.6 - 0.08 = 5.52 = 5.5.

The upper end of the interval is the sample mean added to M. So it is 5.6 + 0.08 = 5.7.

The 85% confidence interval for the mean is between 5.5 and 5.7 fast food meals consumed per week.

3 0
3 years ago
If you subtract -46 from twice a number, the result is 548, how do u find the number
Juliette [100K]
Add -46 and -46 to the final answer
8 0
4 years ago
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