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vovangra [49]
3 years ago
12

The intersecting plane is parallel to the base below. What is the cross section?

Mathematics
2 answers:
disa [49]3 years ago
6 0
B would be the answer
Sergeeva-Olga [200]3 years ago
5 0
An elipse is the answer
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Find the slope of the line that passes through the two given points (-4,3) and (-8,6)
klemol [59]
The slope of the line that passes throught (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given

(-4,3) and (-8,6)
slop=(6-3)/(-8-(-4))=(3)/(-8+4)=3/-4=-3/4

slope is -3/4
4 0
3 years ago
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What is the sum of the liner expressions -3x + 4 and -12x -27
NISA [10]
-3x+ 4=1 and -12x -27=324
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X + Y is equal to 5 x minus Y is equal to 4 find the value of find the value of x square minus y square ​
Grace [21]

Answer: 20

Step-by-step explanation:

x+y=5

x-y=4

---------

x+y=5

x=4+y

--------

(4+y)+y=5

4+y+y=5

 4+2y=5

      2y=1

        y=0.5

        x=4.5

---------

x²-y²=(4.5)²-(0.5)²=20.25-0.25=20

7 0
3 years ago
Which equation is false?
aivan3 [116]
C is false. 9 multiplied by 7 equals 63.
7 0
3 years ago
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And, S2
dangina [55]

<u>Correct Question</u>

In the table shown, the sum of each row is shown to the right of the row and the sum of each column is shown below the column. What is the value of L?

\left|\begin{array}{c|c|c|c}-&-&-&-\\J&K&J&5\\K&K&L&13\\L&J&L&15\\-&-&-&-\\11&7&15\end{array}\right

Answer:

L=7

Step-by-step explanation:

From the first row: 2J+K=5

Therefore: K=5-2J

From the second column, 2K+J=7

Substitute K derived above into 2K+J=7

2K+J=7

2(5-2J)+J=7

10-4J+J=7

-3J=7-10

-3J=-3

J=1

Recall: K=5-2J

K=5-2(1)=3

K=3

From the third column, J+2L=15

1+2L=15

2L=15-1=14

L=7

Therefore, the value of L=7

CHECK:

\left|\begin{array}{c|c|c|c}-&-&-&-\\1&3&1&5\\3&3&7&13\\7&1&7&15\\-&-&-&-\\11&7&15\end{array}\right

4 0
3 years ago
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