The probability all of the students in this class will be present and on time is 3/10. The probability all of the students are p
resent is 2/5. What is the probability that everyone is on time given that everyone is present? Give your answer as a simplified fraction.
1 answer:
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
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Answer A and Answer D along with the ones you picked beforehand
The greatest common factor is 10
If you do 24.75-12.45 you get 12.30. So there you go!
Answer:
5÷9
Step-by-step explanation:
5/9 is a fraction where the numerator is divided by the denominator
5 divide by 9
5÷9
Well for the function of x we have x=t^5+1 and we know t= -1
So you plug in -1 instead of the t and you will get x=(-1)^5+1
Now just resolve that equation to get the value of x
x = (-1)^5+1 = -1+1 = 0 So x=0
Do the same with y and you’ll get y=2
