Question

Does anyone one how to solve this problem

Answer 1

$( \frac{2}{3} - \frac{1}{6} )$÷$( \frac{2}{5} - \frac{1}{3} )$
The first thing you must do it to solve the fractions inside the parentheses first
$\frac{2}{3} - \frac{1}{6} = \frac{4}{6} - \frac{1}{6}$ which is $\frac{3}{6} or \frac{2}{3}$because you must get a common denominator in order to solve. The common denominator is 6. So you must multiply in order to get 6. $\frac{2}{3} *6= \frac{3}{6}$ Then you do the other fraction: $\frac{2}{5} - \frac{1}{3}= \frac{6}{15} - \frac{5}{15}$ which is $\frac{1}{15}$ because 15 is the common denominator and you must multiply the denominator to get 15, thus, you must multiply by the same amount for the numerator. So now it is $\frac{3}{6}$÷$\frac{1}{15}$ but when dividing, you just need to flip-flop the second fraction and then multiply across. Now it is $\frac{3}{6} * \frac{15}{1} = \frac{45}{6}$ But to simplify, you find a common factor which is 3.
45÷3=15 and 6÷3=2 which is now $\frac{15}{2}$
You answer is C)$\frac{15}{2}$