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2 years ago

How many two-digit, positive integers can be formed from the digits 1, 3, 5, and 9, if no digit is repeated?

Mathematics

1 answer:

irga5000 [103]2 years ago

8 0

Answer:

12

Step-by-step explanation:

Using Permutation Formula :

⁴P₂
4! / 2!
4 x 3 x 2! / 2!
4 x 3
12

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Johns collection contains US, Indian and British stamos. If the stamps ratios of US to Indian stamps is 5 to 2, and the ratio of

NARA [144]

Figure out what is the commonality for each ratio.
There are India stamps in each ratio, so India is the commonality.

Now you simply take the two ratios and multiply them until India has the same amount.

So, Multiply the first by 5 to get a ratio of 25 US to 10 Indian
Multiply the second by 2 to get a ratio of 10 Indian to 2 British

Now that you have "10 Indian" in both ratios, they match up
You have 25 US : 10 Indian : 2 British.

Since the answer is only asking for US and British, you only need 25 US : 2 British

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3 years ago

SOMEBODY HELP ME IM DESPERATE

garik1379 [7]

I believe it is the commutative property of multiplication. Commutative property is you can put the numbers in any order and it will have the same end result. I got multiplication because it is multiplication.

Hope this helps!

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3 years ago

Read 2 more answers

How do you do... cos2x-sin2x=1-2sin2x

Bess [88]

$sin (2 \alpha) =2\cdot sin \alpha \cdot cos \alpha \\cos(2 \alpha )=1-2sin^2 \alpha \\-------------------- \\cos2x-sin2x=1-2sin2x\\cos2x+sin2x=1\\1-2sin^2x+2sinx\cdot cosx=1\\-2sinx(sin x-cosx)=0\\ -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\\\\1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\\2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \ cos x \neq 0\\tanx=1\ \ \Leftrightarrow\ \ x_2= \frac{ \pi }{4} +k \pi \ \ and\ \ k\in I$

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3 years ago

Find the measure of the missing side. Round your answer to the nearest tenth. (PYTHAGOREAN THEOREM)

Burka [1]

Answer:

Rounded to the nearest tenth, the length of the missing side is 5.4 in.

Step-by-step explanation:

According to the Pythagorean theorem, $a^{2}+b^{2}=c^{2}$ , where c is the length of the hypotenuse (the longest side), a and b are the lengths of the other two sides. We can use this to solve for the length of the hypotenuse of the right triangle shown in your question (the missing side):

$2^{2}+5^{2}=c^{2}$

This simplifies to $29=c^{2}$ . Now to solve for c (the length of the hypotenuse), we just take the square root of both sides of the equation and solve like so:

$\sqrt{29} =\sqrt{c^{2}}$

This simplifies to c≈5.4 in.

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3 years ago

Using spreadsheets to Organize Data (PLEASE HELP)

katrin [286]

I can give you the first half!
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2 years ago