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3 years ago

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.08

Mathematics

1 answer:

WINSTONCH [101]3 years ago

6 0

Answer:

if 1 quarter = $ 0.25

1 dime = $ 0.10

1 penny = $ 0.01

so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar

therefore we say;

1 Quarter + 8 dimes + 3 penny

: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )

: 0.25 + 0.80 + 0.03 = $ 1.08

Now if you have a 4 Quarters, you have change for $1.

If you have 5 dimes, you have change for 2 Quarters.

If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.

If you have 5 pennies, you have enough change for 1 nickel

Therefore

(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x

(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x

x = 0.75 + 0.4 + 0.04

x = $ 1.19

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Answer:

Step-by-step explanation:

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3 years ago

janice invests a total of 8000 in two different accounts. the first account returns 5%, while the second account returns 8%. if

Zinaida [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

parallel lines so slope of the lines will be equal.

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y = -3x + 5

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3 years ago

nika2105 [10]

Answer:

See Explanation

Step-by-step explanation:

Given

$\triangle ABC = \triangle DE F$

Required

Which would not prove the similarity

$\triangle ABC = \triangle DE F$ implies that:

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$\angle A = \angle D$

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And the following lengths are congruent

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The options are not clear; so, it's a bit difficult to select the correct option.

<em>Any of the options that is different from the above list of 6 congruent pairs is the answer to your question.</em>

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3 years ago

Suppose there is a pile of​ quarters, dimes, and pennies with a total value of ​​$1.08

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.08