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Shalnov [3]
2 years ago
13

Question 5 (10 points)

Mathematics
1 answer:
Kamila [148]2 years ago
5 0
You have to subtract 4.35 from 15.60 to see for all the children
3x+4.35 = 15.60
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What is the x-coordinate of the point shown in the graph? V​
svet-max [94.6K]

Step-by-step explanation:

I dont see a graph can you include the graph

8 0
2 years ago
Reduce to simplest form. -\dfrac{1}{3}-\left(-\dfrac{3}{5}\right)=− 3 1 ​ −(− 5 3 ​ )=minus, start fraction, 1, divided by, 3, e
nevsk [136]

Answer:

-1/3 - (-3/5) = 4/15

Step-by-step explanation:

Reduce to simplest form

-1/3 - (-3/5)

= -1/3 + 3/5

Find the Lowest Common Multiple of 3 and 5

Lowest Common Multiple of 3and 5 is 15

Use the LCM to Simplify

= {(-5*1)+(3*3)} / 15

= (-5+9) / 15

= 4/15

Therefore,

-1/3 - (-3/5) = 4/15

7 0
2 years ago
Read 2 more answers
What’s is the difference between an improper fraction and mixed number
Darya [45]

Answer:

An improper fraction is always 1 or greater than 1. And, finally, a mixed number is a combination of a wholenumber and a proper fraction.In a proper fraction, the numerator is always less than the denominator. Examples ofproper fractions include and 

6 0
2 years ago
The bases of the trapezoid are 6 and 10. The height is 4. Find the area.
ollegr [7]
Answer

b. 32 sq. unit

Step-by-step Explanation

The area of the trapezoid is given by

A = \frac{1}{2} (b_{1} + b_{2}) \times h

We substitute the given values into the formula to obtain;

A = \frac{1}{2}(10 + 6) \times 4

Simplify

A = \frac{1}{2} (16) \times 4

A = 16 \times 2
Hence the area is

A = 36 \: sq \: units
6 0
3 years ago
4. A triangle with base (2x+2) and height (x-2) is cut out of a rectangular sheet of paper that is (3x+4) by (2x+3) what is the
juin [17]
So what we do is
area that remains=total area-triangle area that was cut out


we need to find 2 things
total area
triangle area

total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12

triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4


so
total area=6x^2+17x+12
triangle area=x^2-4

subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16


area that remains is 5x^2+17x+16

5 0
2 years ago
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