Answer:
t = {5}
Step-by-step explanation:
The trajectories intersect at exactly one time, t=5. The point of collision is ...
r1(5) = r2(5) = (25, 25, 25)
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The particles collide when the difference between the coordinates of one of them and the coordinates of the other one is zero. That is, ...
r1(t) - r2(t) = 0
(t^2, 6t -5, t^2) - (9t -20, t^2, 11t -30) = 0
This resolves to three (3) quadratic equations:
- t^2 -9t +20 = 0 . . . . (t -4)(t -5) = 0
- -5 +6t -t^2 = 0 . . . . . -(t -1)(t -5) = 0
- t^2 -11t +30 = 0 . . . . (t -5)(t -6) = 0
These have a common factor of t-5, so will all be zero when t=5.
The particles collide only at t = 5.
Answer:
Undefined
subtract your two points (y-y)/(x-x)
There is only one solution in the given equation -y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0. In solving this problem, apply first PEMDAS (parenthesis, exponents,multiplication, division, addition, subtraction). Then equation will transform into -y2+5y-7y2-9y+15y2+4y=0. Combine terms with same power and achieve 7y2=0. Divide both sides with 7 and perform square root of zero. Since the root is zero, we have one solution of the given equation which is y=0.
Answer:
x=6 as 180 in triangle take away 150 30 by 5 is 6
Answer:
Becky's mistake was that she said , while it's actually equal to .
Step-by-step explanation:
Step 1 looks fine as she just rearranged the equation, keeping the negatives and positives right.
Step 2 is where she said that . This would only be true if we were multiplying one of the numbers by 0. So Step 2 was wrong.
Step 3 is right, as 0+7 = 7.
Hope this helped!